Question

4x²-19+15=0 помогите пожалуйста!!

Answer 1

$\displaystyle\bf\\4x^{2} -19x+15=0\\\\D=(-19)^{2} -4\cdot 4\cdot 15=361-240=121=11^{2} \\\\\\x_{1} =\frac{19-11}{8} =\frac{8}{8} =1\\\\\\x_{2} =\frac{19+11}{8} =\frac{30}{8} =3,75\\\\\\Otvet: \ 1 \ ; \ 3,75$