Question

РЕШИТЕ ПОЖАЛУЙСТА СРОЧНО!!!!

Answer 1

1) $x_{max} = 2$

2) $T = 12$ c

3) ω = $\frac{2\pi }{T} = \frac{2\pi }{12} = \frac{\pi }{6}$Гц

4) $\nu = \frac{1}{T} = \frac{1 }{12}$ Гц

5) $T = 2\pi\sqrt{\frac{l}{g}}\\ T^2=4\pi^2*\frac{l}{g}\\l = \frac{T^2*g}{4\pi^2}\\l = \frac{1* 10}{144* 4 * 3.14 * 3.14}=1,7$(мм)

6) $x(t)=x_{max}\cos(\omega t + \varphi _{0})$

$x(t)=2\cos \frac{\pi t}{6}$