Question

Пожалуйста по быстрее​

Answer 1

$\displaystyle\bf\\1)\\\\\frac{x-5}{4x+4} -\frac{x-2}{x+1} =\frac{x-5}{4(x+1)} -\frac{x-2}{x+1} =\frac{x-5-4\cdot(x-2)}{4(x+1)} =\\\\\\=\frac{x-5-4x+8}{4(x+1) } =\frac{3-3x}{4x+4} \\\\\\2)\\\\\frac{b+2}{2b-8} +\frac{4-b}{3b-12} =\frac{b+2}{2(b-4)} +\frac{4-b}{3(b-4)} =\frac{3\cdot(b+2)+2\cvdot(4-b)}{6(b-4)} =\\\\\\=\frac{3b+6+8-2b}{6(b-4)} =\frac{b+14}{6b-24}$

$\displaystyle\bf\\3)\\\\\frac{c+4}{c-4}-\frac{c-3}{c+4} =\frac{(c+4)\cdot(c+4)-(c-4)\cdot(c-3)}{(c-4)(c+4)} =\\\\\\=\frac{c^{2} +8c+16-c^{2} +3c+4c-12}{(c-4)(c+4)} =\frac{15c+4}{c^{2}-16 }$