Question

(3х-6х/х+5):9х+27/8х+40

Answer 1

$\dfrac{3x-6x}{x+5}:\dfrac{9x+27}{8x+40}=\dfrac{-3x}{x+5}\cdot\dfrac{8(x+5)}{9(x+3)}=-\dfrac{8x}{3(x+3)}=-\dfrac{8x}{3x+9}$