Question

2 вариант помогите срочно

Answer 1

$\left \{ {{3-4x = 3y+3} \atop {2x+2y=5y+8}} \right. \\\left \{ {{-4x-3y = 0} \atop {2x-3y=8}} \right. \\-4x-2x-3y+3y = 0-8\\-6x=-8\\ x= \frac{4}{3} \\2*\frac{4}{3} - 3y = 8\\-3y = \frac{16}{3} \\y= - \frac{16}{9}$$\left \{ {{3x-6y-2 = -2} \atop {2x+2-y = 3x-1}} \right. \\\left \{ {{3x-6y = 0} \atop {-x-y = -3}} \right. \\\left \{ {{x=3-y} \atop {9-3y-6y = 0}} \right. \\\\-9y = -9 \\y = 1\\x= 3-1\\x=2$

(4/3; -16/9)                          (2;1)