Question

помогите срочно умоляю
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Answer 1

1)

$8( \frac{5}{8} + \frac{3a}{8} ) = 8 \times \frac{5}{8} + 8 \times \frac{3a}{8} = 5 + 3a$

$( \frac{7c}{9} - \frac{11}{18} ) \times 18 = \frac{7c}{9} \times 18 - \frac{11}{18} \times 18 = 14c - 11$

2)

$\frac{1}{3} ( \frac{6}{7} a + \frac{3}{4} ) = \frac{1}{3} \times \frac{6}{7} a + \frac{1}{3} \times \frac{3}{4} = \frac{2}{7} a + \frac{1}{4} = \frac{8a}{28} + \frac{7}{28} = \frac{8a + 7}{28}$

$4 \frac{1}{2} (x - \frac{1}{3} ) = \frac{9}{2} x - \frac{9}{2} \times \frac{1}{3} = \frac{9}{2} x - \frac{3}{2} = \frac{9x - 3}{2}$

3)

$15( \frac{5}{6} b - \frac{7}{18} c + \frac{1}{30} ) = 15 \times \frac{5}{6} b - 15 \times \frac{7}{18} c + 15 \times \frac{1}{30} = \frac{25}{2} b - \frac{35}{6}c + \frac{1}{2} = \\ \\ = \frac{75b}{6} + \frac{35c}{6} + \frac{3}{6} = \frac{75b + 35c + 3}{6}$

$1 \frac{1}{6} (2x + \frac{5}{14} y - 1 \frac{1}{2} ) = \frac{7}{6} \times 2x + \frac{7}{6} \times \frac{5}{14} y - \frac{7}{6} \times \frac{3}{2} = \frac{7x}{3} + \frac{5y}{12} - \frac{7}{4} = \\ \\ = \frac{28x}{12} + \frac{5y}{12} - \frac{21}{12} = \frac{28x + 5y - 21}{12}$

Answer 2

Ответ:

Пошаговое объяснение:

1)

8(5/8 + 3а/8) = 40/8 + 24а/8 =

5 + 3а

(7с/9 - 11/18) * 18 = 126с/9 - 198/18 =

14с - 11

2)

1/3(6/7а + 3/4) = 6/21а + 3/12 =

2/7а + 1/4

4. 1/2(х - 1/3) = 9/2(х - 1/3) = 9/2х - 9/6 = 4. 1/2х - 1. 3/6 = 4. 1/2х - 1. 1/2

3)

15(5/6b - 7/18c + 1/30) =

75/6b - 105/18c + 15/30 =

25/2b - 35/6c + 1/2 =

12. 1/2b - 5. 5/6c + 1/2

1. 1/6(2х + 5/14у - 1. 1/2) =

7/6(2х + 5/14у - 3/2) =

14х/6 + 35/84у - 21/12 =

7х/3 + 5/12у - 7/4 =

2. 1/3х + 5/12у - 1. 3/4