Предмет: Физика, автор: lizakalashni

Кусочек пластилина массой 1 кг движется по горизонтальному гладкому полу со скоростью 2 м/с. Навстречу ему движется другой шарик массой 500 г со скоростью 1 м/с и врезается в первый. Удар абсолютно неупругий. Найдите, чему равна выделившаяся в результате удара энергия. Ответ приведите в СИ.

Ответы

Автор ответа: p15

Ответ:

2.25Дж

m1=1кг

m2=0.5кг

V1=2м/c

V2=1м/c

Eобщ-?

Все просто. Нужно найти всю кинетическую энергию, что была до удара. Именно столько выделилось

Eк=mV²/2

Eобщ=1*2²/2+0.5*1²/2=2.25Дж

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