Question

cos135°+tg225°-sin(-210°)

Answer 1

Ответ:

$\cos(135°) + \tan(225°) - \sin( - 210°) = - \frac{ \sqrt{2} }{2} + 1 - \frac{1}{2} = - \frac{ \sqrt{2} }{2} + \frac{1}{2} = \frac{ - \sqrt{2 + 1} }{2}$