Question

(х-3) (х-4) (х-5)=(х-2) (х-4) (х-5)

Answer 1

Объяснение:

$(x - 3)(x - 4)(x - 5) = (x - 2)(x - 4)(x - 5) \\ (x - 3)(x - 4)(x - 5) - (x - 2)(x - 4)(x - 5) = 0 \\ (x - 4)(x - 5)(x - 3 - (x - 2) = 0 \\ (x - 4)(x - 5)(x - 3 - x + 2) = 0 \\ (x - 4)(x - 5) \times ( - 1) = 0 \\ (x - 4)(x - 5) = 0 \\ x - 4 = 0 \: \: \: \: \: \: x - 5 = 0 \\ x = 4 \: \: \: \: \: \: x = 5$