Question

памагити, прашу, умоляю((

Answer 1

$\displaystyle\bf\\\frac{1}{x-2} +\frac{1}{x+2} +\frac{x}{4-x^{2} } -\frac{x^{2} +4}{2x^{3} -8x} =\\\\\\=\frac{1}{x-2} +\frac{1}{x+2} -\frac{x}{(x-2)(x+2) } -\frac{x^{2} +4}{2x(x-2)(x+2)} =\\\\\\=\frac{2x\cdot(x+2)+2x\cdot(x-2)-x\cdot 2x-x^{2} -4}{2x(x-2)(x+2)} =\\\\\\=\frac{2x^{2} +4x+2x^{2} -4x-2x^{2} -x^{2} -4}{2x(x-2)(x+2)} =\\\\\\=\frac{x^{2}-4 }{2x(x-2)(x+2)} =\frac{(x-2)(x+2)}{2x(x-2)(x+2)}=\frac{1}{2x} \\\\\\x=-2,5\\\\\\\frac{1}{2x} =\frac{1}{2\cdot(-2,5)} =-\frac{1}{5} =-0,2$

$\displaystyle\bf\\Otvet:-0,2$