Question

найдите производную функции f(x)=-4x^-4x -6x^0.5+9​

Answer 1

Ответ:

$\displaystyle f(x) = - 4x {}^{ - 4} - 6x {}^{0.5} + 2x + 9$

$\displaystyle f {}^{.} (x) = - 4 \times ( - 4) {x}^{ - 5} - 6 \times \frac{1}{2} {x}^{ - \frac{1}{2} } + 2 \times 1 + 0 = \frac{16}{ {x}^{5} } - \frac{3}{ \sqrt{x} } + 2$

Answer 2

f'(x)=(-4x⁻⁴-6x⁰.⁵+2x+9)'=16x⁻⁵-3/x⁰.⁵+2

(xⁿ)'=n*xⁿ⁻¹

(const)'=0