Question

Алгебра 7 класс решить

Answer 1

${(3 - d)}^{2} = 9 - 6d + {d}^{2}$

${(14 + r)}^{2} = 196 + 28r + {r}^{2}$

${(a - 8)}^{2} = {a}^{2} - 16a + 64$

${(q + 12)}^{2} = {q}^{2} + 24q + 144$

${(p + 15)}^{2} = {p}^{2} + 30p + 225$

${(z - 18)}^{2} = {z}^{2} - 36z + 324$

${(10 - b)}^{2} = 100 - 20b + {b}^{2}$

${(2a + b)}^{2} = 4 {a}^{2} + 4ab + {b}^{2}$

${(a + 4b)}^{2} = {a}^{2} + 8ab + 16 {b}^{2}$

${(5y + 2c)}^{2} = 25 {y}^{2} + 20yc + 4 {c}^{2}$

${(9k - 1)}^{2} = 81 {k}^{2} - 18k + 1$

${(3x + 2)}^{2} = 9 {x}^{2} + 12x + 4$

${(y - 4b)}^{2} = {y}^{2} - 8yb + 16 {b}^{2}$

${(1 + 2y)}^{2} = 1 + 4y + 4 {y}^{2}$

${(3 - 4x)}^{2} = 9 - 24x + 16 {x}^{2}$