Предмет: Химия, автор: oliviaolivka50

Сколько соли и воды нужно, чтобы приготовить 0,2моль раствора нитрата амония?​

Ответы

Автор ответа: pchelkin5
3

Ответ:

Объяснение:

m(NH4NO3) = 0,2 * 80 = 16 г.
А воды любое количество,самое главное,чтобы было 16 г нитрата аммония.

oliviaolivka50: спасибо огромное!
oliviaolivka50: а 80 это что?
pchelkin5: Молярная масса NH4NO3
oliviaolivka50: спасибо!
pchelkin5: 14 + 4 + 14 + 16*3 = 80 г/моль
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