Question

(х-у=5

(-х+2у=-3



решить методом подстановки срочно!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!1

Answer 1

$\displaystyle\bf\\\left \{ {{x-y=5} \atop {-x+2y=-3}} \right. \\\\\\\left \{ {{x=y+5} \atop {-y-5+2y=-3}} \right.\\\\\\\left \{ {{x=y+5} \atop {y=2}} \right. \\\\\\\left \{ {{x=2+5} \atop {y=2}} \right. \\\\\\\left \{ {{x=7} \atop {y=2}} \right. \\\\\\Otvet:(7 \ ; \ 2)$

Answer 2

$x - y = 5 \\ - x + 2y = - 3 \\ \\ \\ \\ x = 5 + y \\ \\ \\ - (5 + y) + 2y = - 3 \\ \\ - 5 - y + 2y = - 3 \\ \\ y = - 3 + 5 \\ \\ y = 2. \\ \\ \\ x = 5 + 2 \\ \\ x = 7.$

ОТВЕТ: (x; y) = (7; 2).