Question

СРОЧНО, РАДИ БОГА ПОМОГИТЕ ПОЖАЛУЙСТА

Answer 1

$\displaystyle\bf\\y=x^{2} +5x-2\\\\(k \ ; \ 4) \ \ \Rightarrow \ \ x=k \ \ ; \ \ y=4\\\\4=k^{2} +5k-2\\\\k^{2} +5k-6=0\\\\D=5^{2} -4\cdot(-6)=25+24=49=7^{2}\\\\\\k_{1} =\frac{-5-7}{2} =-6\\\\k_{2} =\frac{-5+7}{2} =1\\\\Otvet:k_{1} =-6 \ ; \ k_{2} =1$