Question

Помогите Пожалуйста ​

Answer 1

Объяснение:

$((\frac{(b^{2} - 2b + 2)}{ {b}^{2} + 4 }) ^ { - 1} - 1) \times ( {b}^{2} - 2b + 2) = (( \frac{ {b}^{2} + 4 }{(b^{2} - 2b + 2) } ) - 1) \times ( {b}^{2} - 2b + 2) = ( \frac{ {b}^{2} + 4 }{ {b}^{2} - 2b + 2 } ) \times ( {b}^{2} - 2b + 2) - 1 \times ({b}^{2} - 2b + 2) = ( {b}^{2} + 4) - ({b}^{2} - 2b + 2) = b^{2} + 4 - {b }^{2} + 2b - 2 = 2b + 2 = 2(b + 1)$