Предмет: Алгебра, автор: gilvanovroman39

2-3а<=1,помогите решить,очень надо

Ответы

Автор ответа: nessahossler691

0

2-3а<=1

-3а≤1-2

-3а≤-1

а≥-1/3

Автор ответа: OblivionFire

0

Объяснение:

2 - 3а ≤ 1

-3а ≤ 1 - 2

-3а ≤ -1

а ≥ -1 : (-3)

а ≥ 1/3

а ∈ [⅓; +∞).

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