Question

1) (1/2)^-5 > (1/2)^2х+3 2) 5^х^2 <=25 решите пажалуйста

Answer 1

Ответ:

1) $(-4;\infty)$ 2) $[-\sqrt{2}; \sqrt{2} ]$

Объяснение:

1)

$(\frac{1}{2})^{-5}>(\frac{1}{2} )^{2x+3}\\\\ -5<2x+3\\2x>-8\\x>-4$

2)

$5^{x^2}\leq 25\\5^{x^2}\leq 5^2\\x^{2}\leq 2\\(x-\sqrt{2})(x+\sqrt{2})\leq 0\\ -\sqrt{2}\leq x\leq \sqrt{2}$