Question

помогите решить пожалуйста​

Answer 1

Ответ:

1.3x+cy+cx+3y=(3x+3y)+(cy+cx)=3(x+y)+c(x+y)=(3+c)(x+y)

2.5a-5b+ap-bp=(5a-5b)+(ap-bp)=5(a-b)+p(a-b)=(5+p)(a-b)

3.ab+ac-b-c=(ab-b)+(ac-c)=b(a-1)+c(a-1)=(b+c)(a-1)

4.x⁵-3x³+4x²-12=(x⁵+4x²)+(-3x³-12)=x²(x³+4)-3(x³+4)=(x²-3)(x³+4)

5.20a³bc-28ac²+15a²b²-21bc=(20a³bc-28ac²)+(-21bc+15a²b²)=4ac(5a²b-7c)+3b(5a²b-7c)=(4ac+3b)(5a²b-7c)

6.ax²+ay-bx²-by+cx²+cy=(ax²-bx²+cx²)(ay-by+cy)=x²(a-b+c)+y(a-b+c)=(x²+y)(a-b+c)

7.x³-x²+x²y+x-xy+y=(x³-x²+x)+(x²y-xy+y)=x(x²-x+1)+y(x²-x+1)=(x+y)(x²-x+1)

1.ma+mb+4a+4b=(ma+mb)+(4a+4b)=m(a+b)+4(a+b)=(m+4)(a+b)

2.xy+8y-2x-16=(xy+8y)+(-2x-16)=y(x+8)-2(x+8)=(y-2)(x+8)

3.a-1+ab-b=(a+ab)+(-1-b)=a(1+b)-1(1+b)=(a-1)(1+b)

4.c⁶-10c⁴-5c²+50=(c⁶-10c⁴)+(-5c²+50)=c⁴(c²-10)-5(c²+10)=(c⁴-5)(c²+10)

5.24x⁶-44x⁴y-18x²y³+33y⁴=(24x⁶-44x⁴y)+(18x²y³+33y⁴)=4x⁴(6x²-11y)+3y³(6x²-11y)=(4x⁴+3y³)(6x²-11y)

6.a²b+a+ab²+b+3ab+3=ab(a+b+3)+a+b+3=(а+b+3)(ab+1)

7.m²n+mn-5-5m+n-5m²=n(m²+m+1)-5(1+m+m²)=(m²+m+1)(n-5)