Question

tg(2x-π/6)=√3 Помогите решить, очень срочно!

Answer 1

$2x - \frac{\pi}{6} = y$

$\mathrm{tg} y = \sqrt{3}$

$y = \mathrm{arctg} \sqrt{3} + \pi\cdot m$

$m \in \mathbb{Z}$

$y = \frac{\pi}{3} + \pi\cdot m$

$2x - \frac{\pi}{6} = \frac{\pi}{3} + \pi m$

$2x = \frac{\pi}{6} + \frac{\pi}{3} + \pi m = \frac{3\pi}{6} + \pi m =$

$= \frac{\pi}{2} + \pi m$

$x = \frac{\pi}{4} + \frac{\pi m}{2}$

$m \in \mathbb{Z}$