Question

Помогите срочно надо,модно пожалуйста с объяснением через ОДЗ:(х-2)/(x=1)-5/(1-x)=(x^2+27)/x^2-1​

Answer 1

$\displaystyle\bf\\\frac{x-2}{x+1}-\frac{5}{1-x}=\frac{x^{2} +27}{x^{2} -1} \\\\\\ODZ:\\\left \{ {{x-1\neq 0} \atop {x+1\neq 0}} \right. \\\\\\\left \{ {{x\neq 1} \atop {x\neq -1}} \right. \\\\\\\frac{x-2}{x+1} +\frac{5}{x-1} -\frac{x^{2}+27 }{(x-1)(x+1)} =0\\\\\\\frac{(x-2)\cdot(x-1)+5\cdot(x+1)-x^{2} -27}{(x-1)(x+1)} =0\\\\\\\frac{x^{2} -x-2x+2+5x+5-x^{2} -27}{(x-1)(x+1)}=0\\\\\\\frac{2x-20}{(x-1)(x+1)} =0\\\\\\\left \{ {{2x-20=0} \atop {x\neq -1 \ ; \ x\neq 1}} \right.$

$\displaystyle\bf\\\left \{ {{x=10} \atop {x\neq -1 \ ; \ x\neq 1}} \right.\\\\\\Otvet:10$