Question

1) (√18+√2)*2

2) (√11+3)²-6√11

3) (2+√3)²+(2-√3)²

4) (√21*√14)/√6

Answer 1

Ответ:

$1)( \sqrt{18 } + \sqrt{2} ) \times 2 = (3 \sqrt{2} + \sqrt{2} ) \times 2 = 4 \sqrt{2} \times 2 = 8 \sqrt{2}$

$2) (\sqrt{11} + 3) {}^{2} - 6 \sqrt{11} = 11 + 6 \sqrt{11} + 9 - 6 \sqrt{11} = 20$

$3)(2x + \sqrt{3} ) {}^{2} + (2 - \sqrt{3} ) {}^{2} = 4x {}^{2} + 4 \sqrt{3} x + 3 + 4 - 4 \sqrt{3} + 3 = 4x {}^{2} + 4 \sqrt{3} x + 10 - 4 \sqrt{3}$

$4)( \sqrt{21 } \times \sqrt{14} )\div \sqrt{6} = \sqrt{294} \div \sqrt{6} = (7 \sqrt{6} ) \div \sqrt{6} = 7$