Question

разложите на множители
$\frac{1}{8} - b {}^{3}$

$\frac{8}{27} + {z}^{ 3}$
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Answer 1

1) ⅛ - b³ = (½)³ - b³ = (½ - b)(¼ + ½b + b²)

2) 8/27 + z³ = (⅔)³ + z³ = (⅔ + z)(4/9 - ⅔z + z²)