Question

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Answer 1

Ответ:

= 2/3

Объяснение:

$\frac{ log_{2}8 + log_{2}0.5}{ log_{2}16 - log_{2}0.2 - log_{2}10} = \frac{ log_{2}(8 \times 0.5) }{ log_{2}16 - ( log_{2}0.2 + log_{2}10)} = \frac{ log_{2}4}{ log_{2}16 - log_{2}(0.2 \times 10) } = \frac{ log_{2}4 }{ log_{2} \frac{16}{2} } = \frac{ log_{2} {2}^{2} }{ log_{2} {2}^{3}} = \frac{2 \times log_{2}2}{3 \times log_{2}2 } = \frac{2}{3}$