Question

10x²-3x-1=0
решите уравнение.​

Answer 1

$10 {x}^{2} - 3x - 1 = 0 \\ D = b {}^{2} - 4ac = ( - 3) {}^{2} - 4 \times 10 \times ( - 1) = 9 + 40 = 49 \\ x½ = \frac{ - b± \sqrt{D} }{2a} \\ \sqrt{D} = 7 \\ x½ = \frac{3±7}{2 \times 10} = 0.5 \: ; \: - 0.2$

Ответ: х1=0,5

х2=-0,2

Answer 2

10x²-3x-1=0

D=$3^{2}$+10*1*4=9+40=49=$7^{2}$

$x_{1}$=$\frac{3+7}{20}$=$\frac{10}{20}$=0.5

$x_{2\\}$=$\frac{3-7}{20}$=$\frac{-4}{20}$=-0.2

Ответ: $x_{1}$=0,5 $x_{2}$=-0,2