Question

Спростити вираз допоможіть будь-ласка
Даю 35 Балів :)

Answer 1

$\displaystyle\bf\\\frac{2x}{x-3}=\frac{3x+3}{x} \\\\\\\frac{2x}{x-3}-\frac{3x+3}{x}=0\\\\\\\frac{2x\cdot x-(3x+3)\cdot(x-3)}{x(x-3)} =0\\\\\\\frac{2x^{2} -3x^{2} +9x-3x+9}{x(x-3)} =0\\\\\\\frac{-x^{2} +6x+9}{x(x-3)}=0\\\\\\-x^{2} +6x+9=0 \ \ ; \ \ x\neq 0 \ \ , \ \ x-3\neq 0\\\\\\x^{2} -6x-9=0 \ \ ; \ \ x \neq 0 \ \ ; \ \ x\neq 3\\\\\\D=(-6)^{2}-4\cdot (-9)= 36+36=72=(6\sqrt{2} )^{2}$

$\displaystyle\bf\\x_{1} =\frac{6-6\sqrt{2} }{2} =3-3\sqrt{2}\\\\\\x_{2} =\frac{6+6\sqrt{2} }{2} =3+3\sqrt{2}$