Question

27(x-1)(x+1)=3(3x-2)^2+13

Answer 1

Ответ:

$27(x - 1)(x + 1) = 3(3x - 2) {}^{2} + 13 \\ 27(x {}^{2} - 1) = 3(9x {}^{2} - 12x + 4) + 13 \\ 27x { }^{2} - 27 = 27x {}^{2} - 36x + 12 + 13 \\ - 27 = - 36x + 12 + 13 \\ - 27 = - 36x + 25 \\ 36x = 25 + 27 \\ 36x = 52 \\ x = \frac{13}{9}$