Question

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20а²b⁷-12a³b²;
7х²+14х5.

Answer 1

Объяснение:

$20a {}^{2} b {}^{7} - 12a {}^{3} b {}^{2} =4\left(5a^{2}b^{7}-3a^{3}b^{2}\right) =a^{2}b^{2}\left(5b^{5}-3a\right) =4a^{2}b^{2}\left(5b^{5}-3a\right)$

$7x {}^{2} + 14x {}^{5} = 2(2x {}^{2} + 7x {}^{5} ) = x {}^{2} (2 + 7x {}^{3} ) = 2x {}^{2} (2 + 7x {}^{3} )$