Question

[tex](2+1)(2 ^{2}+1)(2^{4}+1)(2^{8}+1) - 2^{16} = ?[tex]

Answer 1

$(2+1)(2^2+1)(2^4+1)(2^8+1)-2^{16}=\ 3*5*17*257-2^{16}=\ 15*17*257-2^{16}=\ (2^4-1)(2^4+1)*(2^8+1)-2^{16}=\ (2^8-1)(2^8+1)-2^{16}=\ 2^{16}-1-2^{16}=-1$
 Ответ -1