Question

1)
$\frac{ {x - 19}^{2} }{x + \sqrt{19} }$
СКОРОТІТЬ ДРІБ И 1 И 2
2)
$\frac{29 - \sqrt{29} }{ \sqrt{29} }$
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Answer 1

$1.\frac{x-19^2}{x+\sqrt{19} } = \frac{x-361}{x+\sqrt{19}} = \frac{x-361}{x+\sqrt{19}} *\frac{x-\sqrt{19} }{x-\sqrt{19} } =\frac{(x-361)(x-\sqrt{19)} }{(x+\sqrt{19})(x-\sqrt{19})} = \frac{x^2-\sqrt{19}x-361x+361\sqrt{19} } {x^2-19}.\\\\\\ 2.\frac{29-\sqrt{29} }{\sqrt{29} }= \frac{29 -\sqrt{29}}{\sqrt{29}} *\frac{\sqrt{29}}{\sqrt{29}} = \frac{(29 -\sqrt{29})\sqrt{29}}{\sqrt{29}\sqrt{29}} = \frac{29\sqrt{29}-29}{29} = \frac{29(\sqrt{29}-1)}{29} =\sqrt{29}-1$Ответ: