Question

Очень прошу помочь. Вот да.​

Answer 1

Задача 5.

${( 5\frac{6}{13} )}^{2} + 2 \times (5 \frac{6}{13} ) \times (3 \frac{7}{13}) + {(3 \frac{7}{13} )}^{2} = \\ \\ = \frac{5041}{169} + \frac{2 \times 71 \times 46}{1 \times 13 \times 13} + \frac{2116}{169} = \\ \\ = \frac{5041 + 6532 + 2116}{169} = \frac{13689}{169} = 81$

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Задача 6

${( 5\frac{6}{13} )}^{2} + 2 \times (5 \frac{6}{13} ) \times (3 \frac{7}{13}) + {(3 \frac{7}{13} )}^{2} = \\ \\ = \frac{5041}{169} + \frac{2 \times 71 \times 46}{1 \times 13 \times 13} + \frac{2116}{169} = \\ \\ = \frac{5041 + 6532 + 2116}{169} = \frac{13689}{169} = 81$

${b}^{6} - 10 a{b}^{3} + 25 {a}^{2} = {( {b}^{3} - 5a) }^{2}$