Question

Помогите пожалуйста решить срочно .

Answer 1

Ответ:

Пошаговое объяснение:

1) f'(x) = 1 - 6x

y0 = f(2) = 2 - 3 * 4 = 2 - 12 = -10

k = f ' (2) = 1 - 12 = -11

y + 10 = -11(x - 2)

y + 10 = -11x + 22

y = -11x + 12

2) f'(x) = 3x^2 + 3

y0 = f(3) = 27 + 9 = 36

k = f ' (3) = 27 + 3 = 30

y - 36 = 30(x - 3)

y - 36 = 30x - 90

y = 30x - 54

3) f'(x) = 2x + 1

y0 = f(-1) = 2 - 1 + 1 = 2

k = f ' (-1) = -2 + 1 = -1

y - 2 = -1(x + 1)

y - 2 = -x - 1

y = -x +1