Question

AC||BD, CK||DM, угол ACK= 48

Answer 1

1) ∆ВДМ=∆АСК
∆ВДМ=48°
∆СДК=3х ∆ЕДМ=х
3х+х+48°=180°
4х=180°-48°
х=132°÷4
х=33

∆СДК=3*33=99° ∆ЕДМ=33°
∆КДЕ=∆КДМ+∆ЕДМ=48°+33°=81°
Ответ: КДЕ=81°