Предмет: Алгебра, автор: nktalitvin369

СРОЧНО ДАЮ 50 БАЛЛОВ!!!!!!!

Приложения:

Ответы

Автор ответа: radumalairau5714

0

Ответ:

1 - все поле

1:6=1/6 (поля/час) - производительность трактористов при совместной работе

1:10=1/10 (поля/час) - производит. І тракториста

1/6 - 1/10 = 1/15(поля/час) - производительность работы ІІ тракториста

1: 1/15= 15(часов) - время вспашки поля ІІ трактористом

Объяснение:

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