Question

помогите пожалуйста дам 50 балов​

Answer 1

$7\sqrt{2}-3\sqrt{8}+4\sqrt{18}=7\sqrt{2}-3*2\sqrt{2}+4*3\sqrt{2}=7\sqrt{2}-6\sqrt{2}+12\sqrt{2}=13\sqrt{2}\\\\(3\sqrt{5}-2)^2=(3\sqrt{5})^2-2*3\sqrt{5}*2+2^2=9*5-6\sqrt{5}+4=45+4-6\sqrt{5}=\\=49-6\sqrt{5}\\\\(7\sqrt{2}-3\sqrt{3}) (7\sqrt{2}+3\sqrt{3})=(7\sqrt{2})^2-(3\sqrt{3})^2=49*2-9*3=98-27=71\\\\\frac{3}{\sqrt{6}}=\frac{3\sqrt{6}}{(\sqrt{6})^2}=\frac{3\sqrt{6}}{6}=\frac{\sqrt{6}}{2}$

$\frac{10}{\sqrt{14}-2}=\frac{10(\sqrt{14}+2)}{(\sqrt{14}-2)(\sqrt{14}+2)}=\frac{10(\sqrt{14}+2)} {(\sqrt{14})^2-2^2}=\frac{10(\sqrt{14}+2)} {14-4}=\frac{10(\sqrt{14}+2)} {10}=\sqrt{14}+2$