Предмет: Математика, автор: bolshacovn

-1\ \frac{\ 1}{6}+\left(-2\ \frac{\ 3}{8}\right)

bolshacovn: -1\ \frac{\ 1}{6}+\left(-2\ \frac{\ 3}{8}\right)

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Автор ответа: buldosev62

0

Ответ:
Что
Что
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