Question

Помогите срочно пожалуйста

Answer 1

Ответ:

$1) \frac{49}{(5\sqrt{21})^{2} } =\frac{49}{25*21}=\frac{49}{525}=\frac{7}{75} \\ 2) \frac{\sqrt{147} }{\sqrt{3} }=\sqrt{\frac{147}{3} }=\sqrt{49 }=7\\ 3) \sqrt{6*40}*\sqrt{90}=\sqrt{6*40*90}=\sqrt{21600}=\sqrt{3600*6}=60\sqrt{6} \\ 4)(\sqrt{37}+2)^{2}=37+4\sqrt{37}+4=41+4\sqrt{37}\\ 5) \frac{\sqrt{22 }*\sqrt{33} }{\sqrt{6} }=\sqrt{\frac{22*33}{6} }=\sqrt{\frac{11*33}{3} }=\sqrt{11*11 }=\sqrt{11^{2} }= 11\\ 6)\sqrt{13} *5\sqrt{2} *\sqrt{26}=\sqrt{13*50*26}=\sqrt{16900}=130$

$7) (\sqrt{12} -\sqrt{3} )\sqrt{3}=\sqrt{36}-\sqrt{9}=6-3=3\\ 8) (\sqrt{13} -3)^{2} +6\sqrt{13}=13-6\sqrt{13}+9+ 6\sqrt{13}=13+9=22$

Объяснение:

Answer 2

Ответ:

$1) = \frac{7}{45 } \\ 2) = \sqrt{ \frac{147}{3} } = \sqrt{49 } = 49 \frac{1}{2} \\ 3) = \sqrt{21600} = 60 \sqrt{6} \\ 4) = 41 + 4 \sqrt{37} \\ 5) = \binom{726}{6} \frac{1}{2} \\ 6) = 130 \\ 7) = (2 \sqrt{3} - \sqrt{3} ) \times 3 = \sqrt{3} \times \sqrt{3} = 3 \\ 8) = 13 - 6 \sqrt{13} + 9 + 6 \sqrt{13} = 22$