Question

$( c+ 4)( c- 4)( {c}^{2} + 16) - ( {c}^{2} - 8) {}^{2}$
при c=-1/4(дробь) ​

Answer 1

Ответ:

$( {c}^{2} - 16)( {c}^{2} + 16) - ( {c}^{4} - 16 {c}^{2} + 64) = {c}^{4} - 256 - {c}^{4} + 16{c}^{2} - 64 = 16 {c}^{2} - 320$

$16 \times ( - \frac{1}{4} )^{2} - 320 = 16 \times \frac{1}{16} - 320 = - 320$

Answer 2

Ответ:

-320

Пошаговое объяснение:

$(c+4)(c-4)(c^2+16)-(c^2-8)^2=(c^2-16)(c^2+16)-(c^4-16c^2+64)=c^4-256-c^4+16c^2-64=-320+16c^2$
$16\cdot(-\frac{1}{4})^2-320=16\cdot\frac{1}{16}-320=-320$