Question

x³-y³=
a³b³-c³=
a³+8=​

Answer 1

1) x³-y³=(x-y)(x²+y²+xy)

2) a³b³-c³=(ab-c)(a²b²+c²+abc)

3) a³+8=(a+2)(a²+4-2a)

Answer 2

Ответ:

$x ^{3} - y {}^{3 } = (x - y) \times (x { }^{2} + xy + y {}^{2} )$

$a {}^{3} b {}^{3} - c {}^{3} = (ab - c) \times (a {}^{2} b {}^{2} + abc + c {}^{2} )$

$a {}^{3} + 8 = (a + 2) \times (a {}^{2} - 2a + 4)$