Question

СРОЧНО ПОМОГИТЕ СРОЧНО

Answer 1

$\displaystyle\bf\\1)\\2Cos0^\circ+5Sin90^\circ-4tg180^\circ=2\cdot 1+5\cdot 1-4\cdot0=2+5=7$

$\displaystyle\bf\\2)\\tg45^\circ Cos30^\cdot Ctg60^\circ=1\cdot \frac{\sqrt{3} }{2}\cdot\frac{1}{\sqrt{3} } =\frac{1}{2} =0,5\\\\\\3)\\\sqrt{(2Sin45^\circ+1)^{2} } -\sqrt{(1-2Cos45^\circ)^{2} } =|2Sin45^\circ+1|-|1-2Cos45^\circ|=\\\\\\=\Big|2\cdot\frac{\sqrt{2} }{2} +1\Big|-\Big|1-2\cdot\frac{\sqrt{2} }{2} \Big|=\Big|\sqrt{2} +1\Big|-\Big|1-\sqrt{2}\Big |=\sqrt{2} +1-(\sqrt{2}-1)=\\\\\\=\sqrt{2} +1-\sqrt{2} +1=2$