Question

Найдите корень уравнения пожалуйста

Answer 1

$\displaystyle\bf\\\sqrt{\frac{1}{1-5x} } =\frac{1}{6} \\\\\\ODZ:\\\frac{1}{1-5x} \geq 0\\\\\\1-5x>0\\\\\\-5x>-1\\\\\\x<0,2 \ \ \Rightarrow \ \ x\in(-\infty \ ; \ 0,2)\\\\\\\Big(\sqrt{\frac{1}{1-5x} } \Big)^{2} =\Big(\frac{1}{6}\Big)^{2} \\\\\\\frac{1}{1-5x} =\frac{1}{36} \\\\\\1-5x=36\\\\\\-5x=35\\\\x=-7\\\\\\Otvet:-7$