Question

ПОМОГИТЕ ОЧ СРОЧНО. ЗАДАНИЕ В ЗАКРЕПЕ!!! ​

Answer 1

Объяснение:

1).

$\frac{2}{x} = \frac{2x + 1}{x} - \frac{4x - 2}{3}$

$2 \times 3 = 3(2x + 1) - x(4x - 2)$

$6 = 6x + 3 - 4 {x}^{2} + 2x$

$4 {x}^{2} - 6x - 2x + 6 - 3 = 0$

$4 {x}^{2} - 8x + 3 = 0$

$d = {( - 8)}^{2} - 4 \times 4 \times 3 = 64 - 48 = 16 \: ( {4}^{2} )$

$x1 = \frac{ - b + \sqrt{d} }{2a} = \frac{ - ( - 8) + \sqrt{16} }{2 \times 4} = \frac{8 + 4}{8} = \frac{12}{8} = 1.5$

$x2 = \frac{ - b - \sqrt{d} }{2a} = \frac{ - ( - 8) - \sqrt{16} }{2 \times 4} = \frac{8 - 4}{8} = \frac{4}{8} = \frac{1}{2}$

2).

$\frac{3}{x - 1} - \frac{12}{x - 2} = 2$

$3(x - 2) - 12(x - 1) = 2(x - 1)(x - 2)$

$3x - 6 - 12x + 12 = 2( {x}^{2} - 2x - x + 2)$

$- 9x + 6 = 2( {x}^{2} - 3x + 2)$

$- 9x + 6 = 2 {x}^{2} - 6x + 4$

$2 {x}^{2} - 6x + 9x + 4 - 6 = 0$

$2 {x}^{2} - 3x - 2 = 0$

$d = {( - 3)}^{2} - 4 \times 2 \times ( - 2) = 9 + 16 = 25 \: ( {5}^{2} )$

$x1 = \frac{ - b + \sqrt{d} }{2a} = \frac{ - ( - 3) + \sqrt{25} }{2 \times 2} = \frac{3 + 5}{4} = \frac{8}{4} = 2$

$x2 = \frac{ - b - \sqrt{d} }{2a} = \frac{ - ( - 3) - \sqrt{25} }{2 \times 2} = \frac{3 - 5}{4} = \frac{ - 2}{4} = - \frac{2}{4} = - \frac{1}{2}$