Question

64 2/3 + (-27) 1/3
помогите

Answer 1

$64^{2/3} =(\sqrt[3]{64} )^{2} = \sqrt[3]{4^{3} } )^{2} =4^{2} =16$

$(-27)^{1/3} =(-3^{3} )^{1/3} =(-3)^{3 *(1/3)} =-3$

$64^{2/3} +(-27)^{1/3} =16-3=13$