Question

срочнооо даю 70 баллов

Answer 1

Ответ:

1 - а

Mr[Al2S3] = Ar[Al] * 2 + Ar[S] * 3 = 27 * 2 + 32 * 3 = 150

ω (Al) = 54 : 150 * 100 = 36 %

ω (S) = 96 : 150 * 100 = 64 %

2 - в

Mr[Ba3N2] = Ar[Ba] * 3 + Ar[N] * 2 = 137 * 3 + 14 * 2 = 440

ω (Ba) = 412 : 440 * 100 = 94 %

ω (N) = 28 : 440 * 100 = 6 %

3 - б

Mr[K2O] = Ar[K] * 2 + Ar[O] = 39 * 2 + 16 = 94

ω (K) = 78 : 94 * 100 = 83 %

ω (O) = 16 : 94 * 100 = 17 %

4 - г

Mr[N2O3] = Ar[N] * 2 + Ar[O] * 3 = 14 * 2 + 16 * 3 = 76

ω (N) = 28 : 76 * 100 = 37 %

ω (O) = 48 : 76 * 100 = 63 %

5 - в

Mr[BeO] = Ar[Be] + Ar[O] = 9 + 16 = 25

ω (Be) = 9 : 25 * 100 = 36 %

ω (O) = 16 : 25 * 100 = 64 %

6 - а

Mr[V2O5] = Ar[O] * 5 + Ar[V] * 2 = 16 * 5 + 51 * 2 = 182

ω (O) = 80 : 182 * 100 = 44 %

ω (V) = 102 : 182 * 100 = 56 %

7 - г

Mr[P2O5] = Ar[P] * 2 + Ar[O] * 5 = 31 * 2 + 16 * 5 = 142

ω (P) = 62 : 142 * 100 = 44 %

ω (O) = 80 : 142 * 100 = 56 %

8. Na2O, MnO2, SO2, CO ⇒ б, в, а, г.

Mr[SO2] = Ar[O] * 2 + Ar[S] = 16 * 2 + 32 = 64

ω (O) = 32 : 64 * 100 = 50 %

ω (S) = 32 : 64 * 100 = 50 %

Mr[Na2O] = Ar[Na] * 2 + Ar[O] = 23 * 2 + 16 = 62

ω (Na) = 46 : 62 * 100 = 74 %

ω (O) = 16 : 62 * 100 = 26 %

Mr[MnO2] = Ar[Mn] + Ar[O] * 2 = 55 + 16 * 2 = 87

ω (Mn) = 55 : 87 * 100 = 63 %

ω (O) = 32 : 87 * 100 = 37 %

Mr[CO] = Ar[C] + Ar[O] = 12 + 16 = 28

ω (C) = 12 : 28 * 100 = 43 %

ω (O) = 16 : 28 * 100 = 57 %

9. CuO, SeO3, SiO2, Cl2O7 ⇒ г, б, в, а.

Mr[Cl2O7] = Ar[Cl] * 2 + Ar[O] * 7 = 35 * 2 + 16 * 7 = 183

ω (Cl) = 71 : 183 * 100 = 39 %

ω (O) = 112 : 183 * 100 = 61 %

Mr[SeO3] = Ar[O] * 3 + Ar[Se] = 16 * 3 + 79 = 127

ω (O) = 48 : 127 * 100 = 38 %

ω (Se) = 79 : 127 * 100 = 62 %

Mr[SiO2] = Ar[O] * 2 + Ar[Si] = 16 * 2 + 28 = 60

ω (O) = 32 : 60.0843 * 100 = 53%

ω (Si) = 28 : 60 * 100 = 47 %

Mr[CuO] = Ar[Cu] + Ar[O] = 64 + 16 = 80

ω (Cu) = 64 : 80 * 100 = 80 %

ω (O) = 16 : 80 * 100 = 20 %

10. RbCl, NaCl, CaCl2, BeCl2 ⇒ г, а, в, б

Mr[NaCl] = Ar[Cl] + Ar[Na] = 35 + 23 = 58

ω (Cl) = 35 : 58 * 100 = 61 %

ω (Na) = 23 : 58 * 100 = 39 %

Mr[BeCl2] = Ar[Be] + Ar[Cl] * 2 = 9 + 35 * 2 = 80

ω (Be) = 9 : 80 * 100 = 11 %

ω (Cl) = 71 : 80 * 100 = 89 %

Mr[CaCl2] = Ar[Ca] + Ar[Cl] * 2 = 40 + 35 * 2 = 111

ω (Ca) = 40 : 111 * 100 = 36 %

ω (Cl) = 71 : 111 * 100 = 64 %

Mr[RbCl] = Ar[Rb] + Ar[Cl] = 85 + 35 = 121

ω (Rb) = 85 : 121 * 100 = 71 %

ω (Cl) = 35 : 121 * 100 = 29 %

Объяснение: