Question

32$1)32\sqrt2-\sqrt48*\sqrt3 = ?\\\\2) (\sqrt5 + 1)^{2} - \sqrt20 = ?$

Answer 1

Ответ:

Объяснение:

1) 32√2-√48*√3=32√2-√(48*3)=32√2-√144=32√2-12

2)(√5+1)²-√20=5+2√5+1-√20=5+2√5+1-2√5=6