Question

Ребята помогите пожалуйста заранее спасибо!!! ПЛИЗЗЗ ​

Answer 1

Ответ:

2.

$3 \times \frac{1}{2} + 2 \times {1}^{2} + { \sqrt{3} }^{2} - \frac{1}{2} = \frac{3}{2} + 2 + 3 - \frac{1}{2} = \frac{2}{2} + 5 = 1 + 5 = 6$

3.

$( \sin^{2} ( \alpha ) - \frac{ \sin^{2} ( \alpha ) }{ \cos^{2} ( \alpha ) } ) \times \cos^{2} ( \alpha ) = \frac{ \sin^{2} ( \alpha ) \cos^{2} ( \alpha ) - \sin^{2} ( \alpha ) }{ \cos ^{2} ( \alpha ) } \times \cos^{2}( \alpha ) = \frac{( \cos^{2}( \alpha ) - 1) \times \sin^{2}( \alpha ) }{ \cos^{2}( \alpha ) } \times \cos^{2}( \alpha ) = \frac{ - (1 - \cos^{2}( \alpha )) \times \sin^{2}( \alpha ) }{ \cos^{2}( \alpha ) } \times \cos^{2}( \alpha ) = \frac{ - \sin^{2}( \alpha ) \times \sin^{2}( \alpha ) }{ \cos^{2}( \alpha ) } \times \cos^{2}( \alpha ) = \frac{ - \sin^{4}( \alpha ) }{ \cos^{2}( \alpha ) } \times \cos^{2}( \alpha ) = - \sin^{4}( \alpha )$