Question

9х²-4х-2=0 помогите пожалуйста​

Answer 1

Ответ:

9x^2-4х-2=0

Д=16+72=88=\sqrt{4*22} =2 \sqrt{22}

4∗22

=2

22

х1=(4-(2 \sqrt{22} )/18(2

22

)/18 =(2-\sqrt{22} )/9

22

)/9

x2=(4+(2 \sqrt{22} )/18(2

22

)/18 =(2+\sqrt{22} )/9

22

)/9

Answer 2

Ответ:

$x1 = \frac{2 + \sqrt{22} }{9}$

$x2 = \frac{2 - \sqrt{22} }{9}$

Объяснение:

$9 {x}^{2} - 4x - 2 = 0$

$d = {( - 4)}^{2} - 4 \times 9 \times ( - 2) = 16 - ( - 72) = 88$

$x1 = \frac{ - b + \sqrt{d} }{2a} = \frac{ - ( - 4) + \sqrt{88} }{2 \times 9} = \frac{4 + 2 \sqrt{22} }{18} = \frac{2 + \sqrt{22} }{9}$

$x2 = \frac{2 - \sqrt{22} }{9}$