Question

12-10(x-y)=14x+8y
6x-5y=3​

Answer 1

$1)12-10(x-y)=14x+8y\\12-10x+10y=14x+8y\\-10x-14x=8y-12-10y\\-24x=-2y-12\\x=\frac{1}{12}y+\frac{1}{2}\\2)6x-5y=3\\6x=3+5y\\x=\frac{1}{2}+\frac{5}{6}y\\x=\frac{5}{6}y+\frac{1}{2}$