Question

Спростіть вираз: фото прилагается

Answer 1

Ответ:

Объяснение:

Фото

Answer 2

$\frac{\cos(\frac{\pi}{2}+\alpha)}{\cos(3\pi+\alpha)}+\frac{\cos(\pi-\alpha)}{\sin(\pi+\alpha)-1}=\frac{-\sin(\alpha)}{\cos(\alpha)}+\frac{-\cos(\alpha)}{-\sin(\alpha)-1}=\frac{\sin(\alpha)}{\cos(\alpha)}-\frac{\cos(\alpha)}{-(\sin(\alpha)+1}=\frac{\sin(\alpha)}{\cos(\alpha)}+\frac{\cos(\alpha)}{\sin(\alpha)+1}=\frac{(\sin(\alpha)+1\cdot\sin(\alpha)+\cos(\alpha)^2}{(\sin(\alpha)+1)\cdot\cos(\alpha)}=\frac{\sin(\alpha)^2+\sin(\alpha)+\cos(\alpha)^2}{(\sin(\alpha)+1)\cdot\cos(\alpha)}=$

$=\frac{1+\sin(\alpha)}{(\sin(\alpha)+1)\cdot\cos(\alpha)}=\frac{1}{\cos(\alpha)}$