Question

(3m-2)²-m² разложить на множители ​

Answer 1

$\displaystyle\bf\\(3m-2)^{2} -m^{2} =(3m-2-m)(3m-2+m)=(2m-2)(4m-2)=\\\\=2\cdot(m-1)\cdot 2\cdot(2m-1)=4(m-1)(2m-1)$